Optimal. Leaf size=138 \[ \frac{c 2^{n-\frac{p}{2}+\frac{1}{2}} \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n-1} (g \sec (e+f x))^p (1-\sin (e+f x))^{\frac{1}{2} (-2 n+p+1)} \, _2F_1\left (\frac{1}{2} (2 m-p+1),\frac{1}{2} (-2 n+p+1);\frac{1}{2} (2 m-p+3);\frac{1}{2} (\sin (e+f x)+1)\right )}{f (2 m-p+1)} \]
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Rubi [A] time = 0.460227, antiderivative size = 138, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.139, Rules used = {2926, 2853, 2689, 70, 69} \[ \frac{c 2^{n-\frac{p}{2}+\frac{1}{2}} \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n-1} (g \sec (e+f x))^p (1-\sin (e+f x))^{\frac{1}{2} (-2 n+p+1)} \, _2F_1\left (\frac{1}{2} (2 m-p+1),\frac{1}{2} (-2 n+p+1);\frac{1}{2} (2 m-p+3);\frac{1}{2} (\sin (e+f x)+1)\right )}{f (2 m-p+1)} \]
Antiderivative was successfully verified.
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Rule 2926
Rule 2853
Rule 2689
Rule 70
Rule 69
Rubi steps
\begin{align*} \int (g \sec (e+f x))^p (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \, dx &=\left ((g \cos (e+f x))^p (g \sec (e+f x))^p\right ) \int (g \cos (e+f x))^{-p} (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \, dx\\ &=\left ((g \cos (e+f x))^{-2 m+p} (g \sec (e+f x))^p (a+a \sin (e+f x))^m (c-c \sin (e+f x))^m\right ) \int (g \cos (e+f x))^{2 m-p} (c-c \sin (e+f x))^{-m+n} \, dx\\ &=\frac{\left (c^2 \cos (e+f x) (g \sec (e+f x))^p (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{m+\frac{1}{2} (-1-2 m+p)} (c+c \sin (e+f x))^{\frac{1}{2} (-1-2 m+p)}\right ) \operatorname{Subst}\left (\int (c-c x)^{-m+n+\frac{1}{2} (-1+2 m-p)} (c+c x)^{\frac{1}{2} (-1+2 m-p)} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{\left (2^{-\frac{1}{2}+n-\frac{p}{2}} c^2 \cos (e+f x) (g \sec (e+f x))^p (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{-\frac{1}{2}+m+n-\frac{p}{2}+\frac{1}{2} (-1-2 m+p)} \left (\frac{c-c \sin (e+f x)}{c}\right )^{\frac{1}{2}-n+\frac{p}{2}} (c+c \sin (e+f x))^{\frac{1}{2} (-1-2 m+p)}\right ) \operatorname{Subst}\left (\int \left (\frac{1}{2}-\frac{x}{2}\right )^{-m+n+\frac{1}{2} (-1+2 m-p)} (c+c x)^{\frac{1}{2} (-1+2 m-p)} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{2^{\frac{1}{2}+n-\frac{p}{2}} c \cos (e+f x) \, _2F_1\left (\frac{1}{2} (1+2 m-p),\frac{1}{2} (1-2 n+p);\frac{1}{2} (3+2 m-p);\frac{1}{2} (1+\sin (e+f x))\right ) (g \sec (e+f x))^p (1-\sin (e+f x))^{\frac{1}{2} (1-2 n+p)} (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{-1+n}}{f (1+2 m-p)}\\ \end{align*}
Mathematica [A] time = 40.1278, size = 139, normalized size = 1.01 \[ \frac{2 \tan \left (\frac{1}{4} (2 e+2 f x-\pi )\right ) (a (\sin (e+f x)+1))^m (c-c \sin (e+f x))^n (g \sec (e+f x))^p \sec ^2\left (\frac{1}{4} (2 e+2 f x-\pi )\right )^{m+n-p} \, _2F_1\left (m+n-p+1,n-\frac{p}{2}+\frac{1}{2};n-\frac{p}{2}+\frac{3}{2};-\tan ^2\left (\frac{1}{4} (2 e+2 f x-\pi )\right )\right )}{f (2 n-p+1)} \]
Antiderivative was successfully verified.
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Maple [F] time = 5.358, size = 0, normalized size = 0. \begin{align*} \int \left ( g\sec \left ( fx+e \right ) \right ) ^{p} \left ( a+a\sin \left ( fx+e \right ) \right ) ^{m} \left ( c-c\sin \left ( fx+e \right ) \right ) ^{n}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (g \sec \left (f x + e\right )\right )^{p}{\left (a \sin \left (f x + e\right ) + a\right )}^{m}{\left (-c \sin \left (f x + e\right ) + c\right )}^{n}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\left (g \sec \left (f x + e\right )\right )^{p}{\left (a \sin \left (f x + e\right ) + a\right )}^{m}{\left (-c \sin \left (f x + e\right ) + c\right )}^{n}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (g \sec \left (f x + e\right )\right )^{p}{\left (a \sin \left (f x + e\right ) + a\right )}^{m}{\left (-c \sin \left (f x + e\right ) + c\right )}^{n}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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